NastyOtter17 can you provide some more info ?

Still feels super hacky tho, think it would be nice to have a simplier way or atleast some nice documentation 

YES you are absolutely correct, we should add it to the Task interface.
Any chance you add a GitHub issue so we do not forget ?

Still feels super hacky tho, think it would be nice to have a simplier way or atleast some nice documentation 🙂
Thanks for your help!

Well I figured it out, thats what your - was for :D

But now you're talking about the case two Tasks have the same metric, right?
I mean in general, whether the task with the largest metric is first, or smallest, because I'd need largest metric, but to me it seems like smallest metric is first. Can the order be inversed?

Will they get ordered ascending or descending?

Good point, I'll check the docs... but I think they do not specify
https://clear.ml/docs/latst/docs/references/sdk/task#taskget_tasks
From the code it seems the ordered is not guaranteed.
You can however pass '-last_update' : order_by which will give you the latest updated first
task_filter = { 'page_size': 2, 'page': 0, 'order_by': ['last_metrics.{}.{}'.format(title, series), '-last_update'] } Task.get_tasks(project_name='examples', task_filter=task_filter)

Hi GreasyPenguin14
Sure you can, although a bit convoluted (I'll make sure we have a nice interface 🙂 )
import hashlib title = hashlib.md5('epoch_accuracy_title'.encode('utf-8')).hexdigest() series = hashlib.md5('epoch_accuracy_series'.encode('utf-8')).hexdigest() task_filter = { 'page_size': 2, 'page': 0, 'order_by': ['last_metrics.{}.{}'.format(title, series)] } queried_tasks = Task.get_tasks(project_name='examples', task_filter=task_filter)

nice, will give it a try

👍

Is this still the best way? Is not working for me 😞

I'll try to test in a new project. Will they get ordered ascending or descending? Does documentation beside your example exist?