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, This Is A Great Tool For Visualizing All Your Experiments. I Wanted To Know That When I Am Logging Scalar Plots With Title As Train Loss And Test Loss They Are Getting Diplayed As Train Loss And Test Loss In The Scalar Tab. I Wanted That The Title Shoul

AgitatedDove14 , this is a great tool for visualizing all your experiments. I wanted to know that when I am logging scalar plots with title as train loss and test loss they are getting diplayed as train loss and test loss in the scalar tab.
I wanted that the title should be loss and under that I should get these two differnet graphs train loss and test loss. Is this possible?
image

  
  
Posted 4 years ago
Votes Newest

Answers 68


If you one each "main" process as a single experiment, just don't call Task.init in the scheduler

  
  
Posted 4 years ago

No. since you are using Pool. there is no need to call task init again. Just call it once before you create the Pool, then when you want to use it, just do task = Task.current_task()

  
  
Posted 4 years ago

no i want all of them in the same experiment

  
  
Posted 4 years ago

but this gives the results in the same graph

  
  
Posted 4 years ago

i mean all 100 experiments in one project

  
  
Posted 4 years ago

so, if I call Task.init() before that line there is no need of calling Task.init() on line number 92

  
  
Posted 4 years ago

This code will give you one graph titled "loss" with two series: (1) trains (2) loss

  
  
Posted 4 years ago

and then log using logger

  
  
Posted 4 years ago

In the side bar you get the title of the graphs, then when you click on them you can see the diff series on the graphs themselves

  
  
Posted 4 years ago

Sure

  
  
Posted 4 years ago

I have to create a main task for example named as main

  
  
Posted 4 years ago

So you want these two on two different graphs ?

  
  
Posted 4 years ago

yes

  
  
Posted 4 years ago

You can do:
task = Task.get_task(task_id='uuid_of_experiment')
task.get_logger().report_scalar(...)

Now the only question is who will create the initial Task, so that the others can report to it. Do you have like a "master" process ?

  
  
Posted 4 years ago

so, like if validation loss appears then there will be three sub-tags under one main tag loss

  
  
Posted 4 years ago

I have one more question?

  
  
Posted 4 years ago

And you want all of them to log into the same experiment ? or do you want an experiment per 60sec (i.e. like the scheduler)

  
  
Posted 4 years ago

I have 100 experiments and I have to log them and update those experiments every 5 minutes

  
  
Posted 4 years ago

then if there are 10 experiments then I have to call Task.create() for those 10 experiments

  
  
Posted 4 years ago

like in the above picture

  
  
Posted 4 years ago

Just so I understand,
scheduler executes main every 60sec
main spins X sub-processes
Each subprocess needs to report scalars ?

  
  
Posted 4 years ago

so I want loss should be my main title and I want two different graphs of train and test loss under that loss

  
  
Posted 4 years ago

like in the sidebar there should be a title called "loss" and under that two different plots should be there named as "train_loss" and "test_loss"

  
  
Posted 4 years ago

It will not create another 100 tasks, they will all use the main Task. Think of it as they "inherit" it from the main process. If the main process never created a task (i.e. no call to Tasl.init) then they will create their own tasks (i.e. each one will create its own task and you will end up with 100 tasks)

  
  
Posted 4 years ago

logger.report_scalar(title="loss", series="train", iteration=0, value=100)
logger.report_scalar(title="loss", series="test", iteration=0, value=200)

  
  
Posted 4 years ago

Before this line, call Task.init

  
  
Posted 4 years ago

then if there are 100 experiments how it will create 100 tasks?

  
  
Posted 4 years ago

and that function creates Task and log them

  
  
Posted 4 years ago

logger.report_scalar("loss-train", "train", iteration=0, value=100)
logger.report_scalar("loss=test", "test", iteration=0, value=200)
notice that the title of the graph is its uniue id, so if you send scalars to with the same "title" they will show on the same graph

  
  
Posted 4 years ago

image

  
  
Posted 4 years ago
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