Is There An Elegant Way Of Accessing A Specific File Entry From A Dataset Without Using Io Operations To Locate The File From The Cache Folder? The File Is Intended To Be Used To Create A Dataframe. At The Moment I'M Using The Code Below. The Problem Is T

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Is There An Elegant Way Of Accessing A Specific File Entry From A Dataset Without Using Io Operations To Locate The File From The Cache Folder? The File Is Intended To Be Used To Create A Dataframe. At The Moment I'M Using The Code Below. The Problem Is T

I found this... It works as long as the initial data files uploaded are converted to csv files (e.g., excel, .sav, .spss etc).

preprocess_task = Task.get_task(task_id='xxx123')
local_csv = preprocess_task.artifacts['data'].get_local_copy()

  				
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	one year ago

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					SkinnyBat30
				
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one year ago