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Is There An Elegant Way Of Accessing A Specific File Entry From A Dataset Without Using Io Operations To Locate The File From The Cache Folder? The File Is Intended To Be Used To Create A Dataframe. At The Moment I'M Using The Code Below. The Problem Is T
There is no natural way to expose single files in Datasets. However it looks like you found an appropriate workaround 🙂
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one year ago
one year ago